add two first valid sequences

This commit is contained in:
2023-08-21 16:12:34 +02:00
parent 69bf3b6387
commit 2db6555139
46 changed files with 10729 additions and 0 deletions

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// préambule asymptote
usepackage("amsmath,amssymb");
usepackage("inputenc","utf8");
usepackage("icomma");
import lib_jl;
unitsize(1cm,2cm);
xlimits(-1.25,10);
ylimits(-0.5,3.5);
xaxis(BottomTop,xmin=-1.25,xmax=10,Ticks("%",extend=true,Step=1),p=linewidth(0.5pt)+gray(0)+dotted);
yaxis(LeftRight,ymin=-0.5,ymax=3.5,Ticks("%",extend=true,Step=1),p=linewidth(0.5pt)+gray(0)+dotted);
xlimits(-1.25,10,Crop);
ylimits(-0.5,3.5,Crop);
real f(real x) {return 1/8*(x-5)^2+3/2;}
pair O=(0,0), I=(1,0), J=(0,1), A=(1,1), D=(3,0), E=(8,0), F=(3,f(3)), G=(8,f(8));
label("$O$",O,4.5000(-0.2121,-0.2121));
label("$I$",I,1.5*S);
label("$J$",J,1.5*W);
label("$A$",A, .125*NE);
filldraw(O--I--A--J--cycle, lightgray, linewidth(1pt));
path Cf=graph(f, 2.5, 8.5, n=400);
draw(Cf, linewidth(1pt));
path domaineD = buildcycle(F--D--E--G, graph(f,3,8));
fill(domaineD, pattern("hachures1"));
//draw(F--G, linewidth(1.5pt));
draw((D.x,D.y-.5)--(F.x,F.y+.5), gray(0)+dashed);
draw((E.x,E.y-.5)--(G.x,G.y+.5), gray(0)+dashed);
label("Domaine $D$", (5.5,1), fontsize(18pt), Fill(white));
label("$\int_{a}^{b} f(t)\; dt$", (5.5,.5), fontsize(18pt), Fill(white));
label("$a$", D, 1.75*S, fontsize(18pt), Fill(white));
label("$b$", E, 1.25*S, fontsize(18pt), Fill(white));
xaxis(axis=YEquals(0),xmin=-1.25,xmax=10,Ticks("%",NoZero,Step=1,Size=1mm),p=linewidth(1pt)+black,Arrow(2mm),true);
yaxis(axis=XEquals(0),ymin=-0.5,ymax=3.5,Ticks("%",NoZero,Step=1,Size=1mm),p=linewidth(1pt)+black,Arrow(2mm),true);
shipout(bbox(0.1cm,0.1cm,white));

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// préambule asymptote
usepackage("amsmath,amssymb");
usepackage("inputenc","utf8");
usepackage("icomma");
import lib_jl;
unitsize(1cm,1cm);
real xmin=-5.5, ymin=-1.5, xmax=5.5, ymax=5.5;
xlimits(xmin,xmax);
ylimits(ymin,ymax);
xaxis(BottomTop,xmin=xmin,xmax=xmax,Ticks("%",extend=true,Step=1),p=linewidth(0.5pt)+gray(0)+dotted);
yaxis(LeftRight,ymin=ymin,ymax=ymax,Ticks("%",extend=true,Step=1),p=linewidth(0.5pt)+gray(0)+dotted);
real F(real x) {return .5*(x+5)*(.5x^2+.25x+.5);}
draw(graph(F,-6,4,n=400),linewidth(1pt)+deepred+solid);
xlimits(xmin,xmax,Crop);
ylimits(ymin,ymax,Crop);
xaxis(axis=YEquals(0),xmin=xmin,xmax=xmax,Ticks("%",beginlabel=true,endlabel=true,begin=true,end=true,NoZero,Step=1,Size=1mm),p=linewidth(1pt)+black,Arrow(2mm),true);
yaxis(axis=XEquals(0),ymin=ymin,ymax=ymax,Ticks("%",beginlabel=true,endlabel=true,begin=true,end=true,NoZero,Step=1,Size=1mm),p=linewidth(1pt)+black,Arrow(2mm),true);
pair O=(0,0), I=(1,0), J=(0,1), A=(-4,0), B=(1,0), C=(-1.5,0);
labelx(Label("$O$",NoFill), 0, SW);
label("$I$",I,SE);
label("$J$",J,NW);
draw(line(A-(0,2),A+(0,2)),deepblue+pen1);
label("$a$",A,SE,deepblue);
path integrale1=buildcycle((A.x, F(A.x))--A--C--(C.x, F(C.x)),graph(F,A.x,C.x));
add("integrale1",hatch(H=.5mm,dir=NE,lightred));
fill(integrale1,pattern("integrale1"));
label(scale(.9)*"$\int_{a}^{c} f(x)\; dx$",((A.x+C.x)/2,2),deepred);
path integrale2=buildcycle((C.x, F(C.x))--C--B--(B.x, F(B.x)),graph(F,C.x,B.x));
add("integrale2",hatch(H=.5mm,dir=NW,lightgreen));
fill(integrale2,pattern("integrale2"));
label(scale(.9)*"$\int_{c}^{b} f(x)\; dx$",((C.x+B.x)/2,.5),deepgreen);
draw(line(B-(0,2),B+(0,2)),deepblue+pen1);
label("$b$",B,SW,deepblue);
draw(line(C-(0,2),C+(0,2)),deepgreen+pen1);
label("$c$",C,SW,deepgreen);
shipout(bbox(0.1cm,0.1cm,white));

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% !TeX root = prof_-_calcul_integral_-_2023_1.tex
\partie{Primitives}
\noindent
Soit les fonctions $f(x) = 2x^2 + 3x + 5$ et $F(x) = \dfrac23 x^3 + \dfrac32 x^2 + 5x + 3$, définies sur $ \mathbb{R} $.\\
\noindent
Quel lien existe entre ces deux fonctions?
\vspace{2cm}
\hrule
\sspartie{Définitions}
\noindent
Dans cette partie, on considère une fonction $f$ définie sur un intervalle $I$ de $ \mathbb{R} $.
\vspace{.4cm}
% Définition
\begin{definition}[primitive]
On dit que $ F $ est une \textbf{primitive} de $ f $ sur $ I $ lorsque $ F $ est dérivable sur $ I $ et $ F'=f $.
\end{definition}
\begin{propriete}[]
Toute fonction continue sur un intervalle $I$ admet une primitive sur cet intervalle.
\end{propriete}
\begin{application}
\vspace{-.4cm}
$ f $ est la fonction définie sur $ \R $ par $ f(x) = e^x+2 $.\\
Déterminer une primitive de la fonction $f$ sur $\R$.
\vspace{1cm}
\end{application}
\vspace{.4cm}
\begin{propriete}[primitives d'une même fonction]
Deux primitives d'une même fonction continue sur un intervalle diffèrent d'une constante.
\Cad que si $F$ est une primitive de $f$ sur $I$, alors la fonction $G_k$ définie sur $I$ par $G_k(x) = F(x) + k$ avec $k \in \mathbb{R}$ est aussi une primitive de $f$.
\end{propriete}
\vspace{.4cm}
\begin{propriete}
Soit $x_0$ et $y_0$ deux réels de $I$.\\
Il existe une unique primitive $F$ de $f$ telle que $F(x_0) = y_0$.\\
Cette valeur s'appelle une condition initiale.
\end{propriete}
\begin{application}[]
Soit la fonction $f(x) = 5x^3 - 8x^2 + \dfrac54$ définie sur $ R $.
\begin{questions}
\item Déterminer l'ensemble des primitives $F_k$, où $k \in \R$ de la fonction $f$.
\item Déterminer la primitive de la fonction $f$ prenant la valeur $25$ en $3$.
\end{questions}
\end{application}
\sspartie{Primitives des fonctions usuelles}
\begin{center}
\small
\begin{tabularx}{1\textwidth}{| >{\centering\arraybackslash}X | >{\centering\arraybackslash}X | >{\centering\arraybackslash}X |}
\hline
\textbf{Fonction $\boldsymbol{f}$} & \textbf{Une primitive $\boldsymbol{F}$} & \textbf{Sur l'intervalle $\boldsymbol{I}$}\\
\hline
\rule[-1ex]{0pt}{5ex}$ f(x)=a $, $ a \in \R $ & $ F(x)=ax+C $ & $ \R $\\[2ex]
\hline
\rule[-1ex]{0pt}{6ex}$ f(x)=x^n $, $ n \in \Z $ et $ n \neq -1 $ & $ F(x)=\dfrac{x^{n+1}}{n+1}+C $ & $\begin{array}{ccr}\R&\text{ si }n\in\N\\ ]-\infty\ ;\ 0[ \text{ ou } ]0\ ;\ +\infty[&\text{ si }n<0\\\end{array}$\\[3ex]
\hline
\rule[-1ex]{0pt}{6ex}$ f(x)=\dfrac1{x^2} $ & $ F(x)=-\dfrac1{x} +C $ & $ ]-\infty\ ;\ 0[ $ ou $ ]0\ ;\ +\infty[ $\\[2ex]
\hline
\rule[-1ex]{0pt}{6ex}$ f(x)=\dfrac1{x} $ & $ F(x)=\ln x +C $ & $ ]0\ ;\ +\infty[ $\\[2ex]
\hline
\rule[-1ex]{0pt}{6ex}$ f(x)=\dfrac1{\sqrt{x}} $ & $ F(x)=2\sqrt{x} +C $ & $ ]0\ ;\ +\infty[ $\\[4ex]
\hline
\rule[-1ex]{0pt}{5ex}$ f(x)=e^{x} $ & $ F(x)=e^x +C$ & $ \R $\\[2ex]
\hline
\rule[-1ex]{0pt}{5ex}$ f(x)=\cos{x} $ & $ F(x)=\sin{x} +C$ & $ \R $\\[2ex]
\hline
\rule[-1ex]{0pt}{5ex}$ f(x)=\sin{x} $ & $ F(x)=-\cos{x} +C$ & $ \R $\\[2ex]
\hline
\end{tabularx}
\end{center}
\vspace{.4cm}
\begin{application}[calcul de primitives (1)]
Calculer les primitives des fonctions suivantes:
\begin{tasks}(4)[style=enumerate]
\task $f(x) = x$
\task $f(x) = x^3$
\task $f(x) = 3x^5+1$
\task $f(x) = \sqrt{x}$
\task $f(x) = \dfrac1{x^2}$
\task $f(x) = \dfrac1{\sqrt{x}}$
\task $f(x) = \dfrac{-2}{x^4} + \dfrac1{\sqrt{x}}$
\task $f(x) = 7\cos x - 2\sin x$
\end{tasks}
\end{application}
\sspartie{Primitives et composition}
\begin{center}
\small
\begin{tabularx}{1\textwidth}{| >{\centering\arraybackslash}X | >{\centering\arraybackslash}X | >{\centering\arraybackslash}X |}
\hline
\textbf{Fonction $\boldsymbol{f}$} & \textbf{Une primitive $\boldsymbol{F}$ sur $\boldsymbol{I}$} & \textbf{Condition sur $\boldsymbol{u}$}\\
\hline
\rule[-1ex]{0pt}{6ex}$ a\, u' $, $ a \in \R $ & $ a\, u + C $ & \\[3ex]
\hline
\rule[-1ex]{0pt}{6ex}$ u'+v' $ & $ u + v + C $ & \\[3ex]
\hline
\rule[-1ex]{0pt}{6ex}$ u'\, u^n $, $ n \in \Z $ et $ n \notin \{-1\; ;\ 0\} $ & $ \dfrac{u^{n+1}}{n+1}+C $ & $u(x) \neq 0 \text{ pour } x\in I \text{ si } n\le -2$\\[3ex]
\hline
\rule[-1ex]{0pt}{6ex}$ \dfrac{u'}{u} $ & $ \ln(u) +C $ & $ u(x)>0,\ x \in I $\\[2ex]
\hline
\rule[-1ex]{0pt}{6ex}$ \dfrac{u'}{u^2} $ & $ -\dfrac1{u} +C $ & $ u(x)\neq 0,\ x \in I $\\[2ex]
\hline
\rule[-1ex]{0pt}{6ex}$ \dfrac{u'}{\sqrt{u}} $ & $ 2\sqrt{u} +C $ & $ u(x)>0,\ x \in I $\\[2ex]
\hline
\rule[-1ex]{0pt}{6ex}$ u'e^{u} $ & $ e^{u} +C $ & \\[2ex]
\hline
\rule[-1ex]{0pt}{6ex}$ \cos(\omega\, x + \varphi) $, $ \omega \in \R $ et $ \varphi \in \R $ & $ \dfrac1{\omega}\sin(\omega\, x + \varphi) + C $ & \\[3ex]
\hline
\rule[-1ex]{0pt}{6ex}$ \sin(\omega\, x + \varphi) $, $ \omega \in \R $ et $ \varphi \in \R $ & $ -\dfrac1{\omega}\cos(\omega\, x + \varphi) + C $ & \\[3ex]
\hline
\end{tabularx}
\end{center}
\vspace{.4cm}
\begin{application}[calcul de primitives (2)]
Calculer les primitives des fonctions suivantes:
\begin{tasks}(4)[style=enumerate]
\task $ f(x) = \dfrac{2x}{x^2+1} $
\task $ f(x) = (x+1)\e^{x^2+2x+1} $
\task $ f(x) = \dfrac{x}{\sqrt{x^2+1}} $
\task $ f(x) = \cos(2x + 7) $
\task $ f(x) = \dfrac{x^3}{\left( x^4+1 \right)} $
\task $ f(x) = \sin x\, \cos^3 x $
\task $ f(x) = \tan x $
\task $ f(x) = \dfrac{\sin x}{\cos^2 x } $
\end{tasks}
\end{application}

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% !TeX root = prof_-_calcul_integral_-_2023_1.tex
\newpage
\partie{Intégration}
\sspartie{Notion d'aire}
\begin{definition}[intégrale]
On appelle intégrale de la fonction $f$ entre $a$ et $b$ est l'aire signée sous la courbe de $f$.
\begin{center}
\includegraphics[scale=.3]{fig1.png}
\end{center}
Ceci signifie qu'on compte positivement les aires situées au-dessus de l'axe des abscisses et négativement celles situées en-dessous, puis qu'on en fait la somme.\\
\noindent
On note alors cette intégrale \(\int_{a}^{b} f(x)\; dx\) et on lira <<intégrale de \(a\) à \(b\) de \(f(x)\)>>.
\end{definition}
\noindent
$\int_{a}^{b} f(x)\; dx$ peut être interpréter comme la <<somme infinie>> des aires $f(x) \times dx$ des rectangles infinitésimaux de hauteur $f(x)$ et de largeur $dx$.
\vspace{-8pt}
\begin{center}
\begin{tabular}[c]{ccc}
\includegraphics[scale=.25]{fig2.png} & \hspace{.4cm} & \includegraphics[scale=.2]{fig3.png}
\end{tabular}
\end{center}
\begin{multicols}{2}
\noindent
Sur l'intervalle $[a\ ;\ b]$ l'aire sous la courbe est la surface du domaine hachuré $D$.\\
Cette aire est donc obtenue par calcul de \(\int_{a}^{b} f(t)\; dt\).
\noindent
L'unité d'aire est donnée par la surface du rectangle $OIAJ$.\\\\
\columnbreak
\begin{center}
\includegraphics[scale=.6]{fig4.pdf}
\end{center}
\end{multicols}
\sspartie{Calcul d'intégrales}
\begin{propriete}[calcul d'une intégrale]
Soit $F$ une primitive de $f$ sur l'intervalle $I$. Alors: \qquad $\int_{a}^{b} f(x)\; dx = [F(x)]_{a}^{b} = F(b)-F(a)$.
\end{propriete}
\begin{remarque}
Dans l'écriture \(\int_{a}^{b} f(x)\; dx\), la lettre $x$ est une variable <<muette>>. Ainsi: $\int_{a}^{b} f(x)\; dx = \int_{a}^{b} f(y)\; dy = \int_{a}^{b} f(t)\; dt = \int_{a}^{b} f$
\end{remarque}
\medskip
\begin{propriete}[]
\begin{tasks}(3)[style=enumerate]
\task \(\int_{a}^{a} f(x)\; dx = 0 \)
\task \(\int_{a}^{b} f(x)\; dx = -\int_{b}^{a} f(x)\; dx \)
\task \(\int_{a}^{a} k\; dx = k\, \left(b-a\right) \)
\end{tasks}
\end{propriete}
\medskip
\begin{application}[calculer une intégrale depuis une primitive]
Calculer :
% Questions
\begin{tasks}(2)
\task $ A = \int_{1}^{4} \dfrac3{x^2}\; dx $
\task $ B = \int_{2}^{5} (3t^2+4t-5)\; dt $
\task $ C = \int_{-1}^{1} 2t^2-1\; dt $
\task $ D = \int_{-1}^{1} 2+e^{-2x}\; dx $
\end{tasks}
\end{application}
\sspartie{Propriétés de l'intégrale}
\begin{propriete}[relation de Chasles]
Soit \(f\) une fonction continue sur un intervalle $ I=[a\ ;\ b] $. Soit $ c $ un réel de $ I $.
\begin{center}
\begin{tabular}{cc}
\rule[-1ex]{0pt}{2.5ex}
\begin{minipage}{.4\textwidth}
\[
\int_{a}^{b} f(x)\; dx = \int_{a}^{c} f(x)\; dx + \int_{c}^{b} f(x)\; dx
\]
\end{minipage}
&
\begin{minipage}{.7\textwidth}
\includegraphics[scale=.7]{fig5.pdf}
\end{minipage}
\end{tabular}
\end{center}
\end{propriete}
\medskip
\begin{propriete}[linéarité]
\vspace{-.4cm}
Soient \(f\) et \(g\) deux fonctions continues sur un intervalle $ I=[a\ ;\ b] $ et $\lambda$ un réel quelconque.
\[
\int_{a}^{b} (f(x) + \lambda\, g(x))\; dx = \int_{a}^{b} f(x)\; dx + \lambda\, \int_{a}^{b} g(x)\; dx
\]
\end{propriete}
\medskip
\begin{propriete}[inégalité]
Soient \(f\) et \(g\) deux fonctions continues sur un intervalle $ I=[a\ ;\ b] $.
\begin{itemize}
\item Si pour tout $ x \in [a\ ;\ b], f(x) \geq 0 $, alors $ \int_{a}^{b} f(x)\; dx \geq 0 $ ;
\item Si pour tout $ x \in [a\ ;\ b], f(x) \geq g(x) $, alors $ \int_{a}^{b} f(x)\; dx \geq \int_{a}^{b} g(x)\; dx $.
\end{itemize}
\end{propriete}
\medskip
\begin{application}[]
\vspace{-.4cm}
\small
% Questions
\begin{questions}
\item Calculer $ \int_{1}^{e} \dfrac1{x}\; dx $.
\item
% Questions
\begin{questions}
\item Justifier que la fonction $ x \mapsto \dfrac1{x+1} $ a pour primitive sur $ ]-1\ ;\ +\infty[ $ la fonction $ x \mapsto \ln(x+1) $.\\
On admettra que la dérivée d'une fonction sous la forme $ \ln(u) $ est $ \dfrac{u'}{u} $.
\item Calculer $ \int_{1}^{e} \dfrac1{1+x}\; dx $.
\end{questions}
\item Démontrer que pour tout $ x > 0 $, $ \dfrac1{x(x+1)} = \dfrac1{x}-\dfrac1{x+1}$
\item En déduire la valeur de $ \int_{1}^{e} \dfrac1{x(x+1)}\; dx $.
\end{questions}
\end{application}
\medskip
\begin{propriete}[valeur moyenne d'une fonction sur un intervalle]
% \underline{\textbf{Graphiquement :}}
\begin{center}
\begin{tabular}{l c r}
\begin{minipage}{.4\textwidth}
\noindent
On appelle valeur moyenne de $ f $ sur $ I $ le nombre réel:
\[
m = \dfrac1{b-a}\, \int_{a}^{b} f(x)\, dx
\]\\
\noindent
L'aire sous la courbe représentative de $ f $ (en rouge ci-contre) est égale à l'aire sous la droite d'équation $ y = m $ (en bleu).
\end{minipage}
&
\hspace{.5cm}
&
\begin{minipage}{.7\textwidth}
\includegraphics[scale=.5]{fig6.pdf}
\end{minipage}
\end{tabular}
\end{center}
\end{propriete}
\medbreak

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% !TeX root = prof_-_calcul_integral_-_2023_1.tex
\partie{Intégration par parties}
\begin{propriete}[]
\vspace{-.4cm}
Soit $ u $ et $ v $ deux fonctions dérivables sur $ [a\ ;\ b] $ de dérivées $ u' $ et $ v' $ continues, alors :
\[
\int_{a}^{b} uv'(x)\; dx = \left[ u\; v(x)\right ]_{a}^{b} - \int_{a}^{b} u'v(x)\; dx
\]
\end{propriete}
% remarque
\begin{remarque}
Le choix de $ u $ et $ v' $ est à faire judicieusement puisqu'il faut pouvoir trouver une primitive de $ u'v $.
\end{remarque}
\medskip
\begin{application}[intégration par partie]
\vspace{-.4cm}
Calculer $ \int_{0}^{1} x\e^{x}\; dx $.
%
% \noindent
% On ne peut pas trouver une primitive de $ x \mapsto x\e^{x} $ car non de la forme $ u'\e^{u} $.\\
% On intègre par partie :
%
% \[
% \begin{array}{rcl}
% u(x) = x & & u'(x) = 1 \\
% v'(x) = \e^{x} & & v(x) = \e^{x}
% \end{array}
% \]
%
% \[
% \int_{0}^{1} x\e^{x}\; dx = \left[ x\e^{x} \right]_{0}^{1} - \int_{0}^{1} \e^{x} \times 1\; dx = \left[ x\e^{x} \right]_{0}^{1} - \int_{0}^{1} \e^{x} \; dx = \left[ x\e^{x} \right]_{0}^{1} - \left[\e^{x} \right]_{0}^{1} = (\e - 0) - (\e - 1) = 1.
% \]
\end{application}
\medskip
% application
\begin{application}[déterminer une primitive]
\vspace{-.4cm}
Déterminer une primitive de $ \ln $ sur $ ]0\ ;\ +\infty[ $.
\end{application}

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% File : prof_-_calcul_integral_-_2023_1.tex
% Author : Jeff Lance <email@jefflance.me>
% Date : 18.08.2023 12:20:01
% Last Modified Date: 18.08.2023 12:20:01
% Last Modified By : Jeff Lance <email@jefflance.me>
\documentclass[11pt]{jl-cours}
\usepackage{cancel}
\usepackage{asymptote}
\begin{document}
\pagenumbering{arabic}
\titre{\Jd\ Calcul intégral}{\Jd\ Calcul intégral}
\lohead*{BTS2E}
\rofoot*{\anneescolaire}
Dans ce document, $ f $ est une fonction définie et continue sur un intervalle $ I=[a\ ;\ b] $ de $ \R $.
% Primitives
\import{.}{partieI.tex}
% Intégration
\import{.}{partieII.tex}
% Intégration par parties
\import{.}{partieIII.tex}
\end{document}